What is the mass of 2.20 x 1022 atoms of Xe? 0 4.80 X 10^ 46
0 4.5 X 10^46
valos
0 4.70 X 10 4 46
0 4.80 X 10 4 22

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

50.23 i believe is correct but don't quote me on that.