Given the following equation: 2 KClO3 → 2 KCI + 3 02. How many liters of oxygen are produced by reacting 12.0 moles of KCIO3

403.2 L of O2

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KClO3 —> 2KCI + 3O2

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Next, we shall determine the number of mole of O2 produced by the decomposition of 12 moles of KClO3. This can be obtained as follow:

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Therefore, 12 moles of KClO3 will decompose to produce = (12 × 3)/2 = 18 moles of O2.

Thus, 18 moles of O2 is produced.

Finally, we shall determine the volume of O2 produced from the reaction. This can be obtained as illustrated below:

Recall: 1 mole of any gas occupy 22.4 L at STP.

1 mole of O2 occupies 22.4 L at STP.

Therefore, 18 moles of O2 will occupy = 18 × 22.4 = 403.2 L at STP.

Thus, 403.2 L of O2 is produced from the reaction.

hi my dude or dudette

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )