Balance the following equation: _ H202 --> _H20+_02
When the equation is balanced, what would be the coefficient in front of H20
Type your answer...

Given :

A chemical equation :

H₂O₂ → H₂O + O₂

Solution :

We can see that there are 2 oxygen atoms in LHS and 3 on RHS .

So, we can reduce the oxygen atoms to two in THS by just dividing it by 2.

H₂O₂ → H₂O + O₂

Now, multiplying both sides by 2, we get :

2H₂O₂ → 2H₂O + O₂

Therefore, the balanced chemical equation is 2H₂O₂ → 2H₂O + O₂ .

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally

answer: semi-infinite solid initially at a uniform temperature of 400 ◦c is cooled at its surface by convection. the cooling fluid at a constant temperature of 200 ◦c has a convective coefficient (ha) of 250 w/m2.k. the physical properties of the solid: k = 20 w/m.k and α = 4 * 10-5  m2/s. using δx = 0.04 m and δt = 10 s. write the finite difference equations describing the transient heat transfer of the first five δx and the temperature profile after 30 s.