Heat of fusion: Hf = 334 J/g, Q = m. Hf Heat of vaporization: Hv = 2260 J/g, Q = m. Hv
2.1 J/g˚C Heat capacity (S) of solid water Q = m. S. ΔT
2.03 J/g˚C Heat capacity (S) of water vapor Q = m. S. ΔT
4.18 J/g˚C Heat capacity (S) of liquid water Q = m. S. ΔT

Please show all your work (five steps) to get full credit for this part.

1. How much energy (in KJ) is required to convert 50.0g of ice at – 30 ˚C to
steam at130˚C.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml