0.450 moles of oxygen gas is subjected to a pressure of 3.00 atm and 75 oC. What is it's volume (in Liters)?

Use this formula PV=nRT

Rearrange formula , question want V ,so

V=nRT/P

given

P= 3.00 atm

n=0.450 moles

R is ideal gas constant = 0.08206 L atm mol-¹K-¹

T in Kelvin so , (75 + 273)= 348 Kelvin (K)

Then insert all this information given with that rearranged formula V=nRT/P

5.6⋅10−^19  j

do you need the explaination?