determine the vapor pressure in atm of water in an aqueous solution of 12% BY MASS EHTYLEENE GLYCOL (ANITFREEZE) IF THE VAPOR PRESSURE OF

The given question is incomplete, the complete question is:

Determine the vapor pressure (in atm) of water in an aqueous solution of 12% by mass ethylene glycol (antifreeze) if the vapor pressure of pure water at that temperature is 0.095 atmospheres.

The correct answer is 0.091 atm.

Explanation:

Based on the given information, the mass of ethylene glycol is 12% by mass, which means 12 grams of ethylene glycol dissolved in 88 grams of water.

The moles of a substance can be determined by using the formula,

Moles = Weight/molecular mass

Number of moles of water = mass/molecular mass

= 88g/18g/mol

= 4.88 moles

Number of moles of ethylene glycol = Mass/molecular mass

= 12 grams/62g/mol

= 0.193 moles

Mole fraction of water will be,

Mole fraction = number of moles of water/Number of moles of water+Number of moles of ethylene glycol

Mole fraction = 4.88/4.88+0.193

= 0.961

Vapor pressure of water can be determined by using the formula,

Vapor pressure = Vapor pressure of pure water * Mole fraction of water

= 0.095 * 0.961

= 0.091 atm.