What would be the new pressure if a 400 mL gas sample at 380 mm Hg is expanded to 800 mL with no change in temperature

25 atm or 190mmHg

Explanation:

Since Temperature is constant we dont need to worry about it so.

P1V1=P2V2

Rewritten as (P1xV1)/V2 Always use liters in gas laws

I Prefer atm so ill convert to that to use in the equation.

(.5atmx.4L)/.8L =.25 atm or 190mmHg

(You can convert mmHg to atm by dividing by 760)

lol for the pointsss

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole