Jorge se mueve a razón de 2.45 m/s mientras corre bicicleta por una vereda de un parque; la cual tiene un a trayectoria total de 1.5 km. ¿Cuánto tardó Jorge en hacer ese recorrido?.

Jorge moves at a rate of 2.45 m / s while cycling along a path in a park; which has a total trajectory of 1.5 km. How long did Jorge take to make that journey?

Time taken = 612.24 s=10.2 minute

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration  

• At constant velocity motion:  

the speed of vo = v = constant  

acceleration = a = 0  

Δx = vt or x = xo + vt  

An equation of constant velocity motion  

d = distance = m  

v = speed = m / s  

t = time = seconds  

v=2.45 m / s

d=1.5 km=1500 m

Time taken :

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol