Calculating Mass, Moles, Atoms, and Molecules Worksheet DIRECTIONS: Using the masses on the periodic table, calculate the desired quantity.

1.1.5413×1017 atoms of Ca to grams

2.95.45 grams of SF4 to moles

3.95.6 moles of Sr to grams

4.34.35 moles of Ga to atoms

5.544.6 moles of DyPO4 to grams

6.780.5 grams of Zn5(P3O10)2 to moles

7.2.25104 moles of BF3 to molecules

8.4.3453×1022 molecules As2O5 to grams

9.75.56 moles of Al(NO3)3 to grams

10.Chloral hydrate (C2H3O2Cl3) was used as a sedative and hypnotic.

a. What is the molar mass of chloral hydrate?

b. How many moles of chloral hydrate are in 500.0 grams chloral hydrate?

c. How many atoms of chlorine are in 500.0 grams of chloral hydrate?

d. What mass of chloral hydrate would contain 1.600×1022 atoms of oxygen?

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied