How many moles of helium gas are contained in a presurized gas cylinder with an internal volume of 10.0 L at a pressure of 8.91 atm and a temperature of 287.4 K?

n = 3.77 mol

Explanation:

Given data:

Number of moles = ?

Volume of gas = 10.0 L

Pressure = 8.91 atm

Temperature = 287.4 K

Solution:

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

by putting values,

8.91 atm × 10.0 L = n × 0.0821 atm.L/ mol.K ×287.4 K

89.1 atm.L = n × 23.60 atm.L/ mol

n =89.1 atm.L / 23.60 atm.L/ mol

n = 3.77 mol

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hope i !

i think its 100

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