Determine the pH of a 2.0 x 10-2 M Sr(OH)2 solution.

pH of the Sr(OH)₂ solution : 12.6

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.  

pH = - log [H⁺]  

Sr (OH) ₂ solution is a base with valence 2, so we determine the pOH from the OH ion concentration - which is expressed by pOH = - log [OH -]. After that we determine the pH value from the relationship:

[H⁺] [OH⁻] = Kw=10⁻¹⁴

pH + pOH = 14

Sr(OH)₂⇒Sr²⁺+2OH⁻

From equation [Sr(OH)₂] : [OH⁻]=1 : 2, so [OH⁻]=

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.