The teal line of the hydrogen emission spectrum has a wavelength of 486.0 nm.486.0 nm. Calculate the energy of one photon of this light.

4.086 × 10⁻¹⁹ J

Explanation:

Step 1: Given and required data

Step 2: Convert "λ" to meters

We will use the conversion factor 1 m = 10⁹ nm.

486.0 nm × 1 m/10⁹ nm = 4.860 × 10⁻⁷ m

Step 3: Calculate the energy of one photon of this light

We will use the Planck-Einstein's relation.

E = h × c / λ

E = 6.626 × 10⁻³⁴ J.s × 2.997 × 10⁸ m/s / 4.860 × 10⁻⁷ m

E = 4.086 × 10⁻¹⁹ J

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

it is b that is the answer.