A sample of gas occupies a volume of 571.5 mL at 0.944 atm and 10 oC. Determine the pressure of this sample at 1.183 L and 32 oC.

0.491 atm

Explanation:

Initial volume V1 = 571.5 mL = 0.5715 L

Initial Pressure P1 = 0.944 atm

Initial Temperature T1 = 10 oC + 273 = 283 K (Converting to kelvin units)

Final Temperature T2 = 32 oC + 273 = 305K (Converting to kelvin units)

Final volume V2 = 1.183 L

Final Pressure P2 = ?

These parameters related by the combined gas law;

P1V1 / T1   = P2V2 / T2

Mke P2 subject of formular;

P2 = P1 V1 T2 / V2 T1

P2 = 0.944 * 0.5715 * 305  /  1.183 * 283

P2 = 0.491 atm

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).