At 25°C, the standard enthalpy of formation of HF(aq) is −320.1 kJ/mol. Of OH−(aq), it is −229.6 kJ/mol. Of F−(aq), it is −329.9 kJ/mol, and of H2O(l), it is −285.8 kJ/mol. (a) Calculate the standard enthalpy of neutralization of HF(aq):
HF(aq) + OH−(aq) → F−(aq) + H2O(l)
(b) Using the value of -56.2 kJ as the standard enthalpy change for the reaction
H+(aq)+OH−(aq)→H2O(l)
calculate the standard enthalpy change for the reaction
HF(aq)→H+(aq)+F−(aq)