Substance Specific Heat Capacity
0.290 J/g • °C
Sand
Aluminum
0.902 J/g • °C
Iron
Silver
0.444 J/g • °C
0.240 J/g • °C
0.129 J/g • °C
Gold
1. If 750 g of iron absorbs 22,000 joules, what will the change in temperature be?

ΔT = 66.06°C

Explanation:

Given data:

Mass of iron = 750 g

Heat absorbed = 22000 j

Change in temperature = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

specific heat capacity of iron is 0.444 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

By putting values,

22000 j = 750 g × 0.444 J/g.°C × ΔT

22000 j = 333 J/°C × ΔT

ΔT = 22000 j  /333 J/°C

ΔT = 66.06°C

your answer is c) plasma

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