How many grams of solid lithium hydroxide must be used to prepare 450
mL of 0.55M LiOH solution?

Mass = 6.706 g

Explanation:

Given data:

Mass of lithium hydroxide = ?

Volume of lithium hydroxide = 450 mL (450/1000 = 0.450 L)

Molarity of lithium hydroxide = 0.55 M

Solution:

Formula:

Molarity = number of moles / volume in L

0.55 M = number of moles / 0.450 L

Number of moles = 0.55 M × 0.450 L

Number of moles = 0.25 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.25 mol × 23.95 g/mol

Mass = 6.706 g

it takes on an electronical energy

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole