5.00 ml of an H2SO4 solution with unknown molarity was diluted with 25.00 ml. This was tirated with 15.00ml of .1000 M NaOH to reach the equivalence point. What is the molarity of the original unknown H2SO4 solution? Also, what would the balanced chemical equation for this reaction be?

0.1500 M

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

Explanation:

The balanced chemical equation is:

First we calculate how many NaOH moles reacted, using the volume and concentration:

Then we convert NaOH moles into H₂SO₄ moles:

This amount of H₂SO₄ moles was originally contained within 5.00 mL of solution, thus the molarity is:

i'm assuming that the correct answer is indeed the first one/ "a"..

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)