A 1000-g iron frying pan is placed on a stove. The pan increases from 20°C to 130°C. If the specific heat of iron is 0.444 J/goC, how much heat was gained by the pan?

48,840 Joules

Explanation:

The equation you should use for this problem is Q=m c ΔT

Now just substitute based of of what you know.

We do not know what Q is. M equals 1,000 grams. C equals .444 the specific heat capacity. Delta T equals 110.

*To find T you must subtract 130-20 degrees to find the change.

The final equation should be: Q= 1000×.444×110

Now all you do is solve like you would normally and the answer you should get is: 48,840.

And so that how the answer comes out :D

i dont know its just needed points lol

Explanation:

I will put answer in th  repiles

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied