I NEED THIS FOR EXAM A template of a Venn diagram representing common and differentiating characteristics of covalent and ionic bonds is shown.

Two overlapping circles are shown. On top of the left-hand circle Ionic Bond is written and on top of the right-hand circle Covalent bond is written. The non-overlapping space on the left is marked A, the overlapping space is marked B and the non-overlapping space on the right is marked C.

Which of the following characteristics can be written only in space B?

Occurs in substances that have at least one non-metal

Occurs in substances that have a repeating lattice structure

Occurs in substances that have discrete molecular structure

Occurs in substances that have high melting points

The characteristic that can be written only in space B is : ( A ) Occurs in substances that have at least one non-metal

The overlapping space of the two circles representing ionic and covalent bonds can be marked as " occurs in substances that have at least one non-metal "  this is because in an ionic bond a metal and a non-metal exchanges their outermost electrons.  while

A covalent bond involves the sharing of outermost electrons by non-metals to attain octet configuration.

Hence we can conclude that the characteristic that can be written only in space B is " Occurs in substances that have at least one non-metal.

Learn more about Ionic bonds : link

Occurs in substances that have at least one non-metal

Explanation:

The overlapping sets which is denoted by the region B is best attributed to connote with the choice "occurs in substance that have at least one non-metal".

To form an ionic bond, a metal and a non-metal must exchange electrons in order to an electrostatic attraction to occur.

In the case of covalent bonds, non-metals shares their valence electrons to form a bond by attaining an octet configuration.

So, we see that a pre-requisite for both bonds to form is a minimum of the presence of a non-metal.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.