Which of the following changes would double the force between two charged particles

Decreasing the distance between the particles by a factor of 2

Explanation:

To double the force between the two charge particles, the distance between the particles should be reduced by a factor of two.

According to coulombs law "force is directly proportional to the potential between the two charges and inversely proportional to the square of their distances".

       F  =

F is the electric force

k is the coulomb constant

q is the charge

r is the distance or separation

As the separation between the charges is reduced the force increases and vice versa

a patient chooses to not take a beneficial medical treatment.

explanation:

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it