Convert this word equation into a balanced formula equation, please. Copper (II) nitrate reacts with aluminum to form aluminum nitrate and copper.

3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu

Explanation:

From the question given above,

Copper (II) nitrate reacts with aluminum to form aluminum nitrate and copper. This can be obtained represent as follow:

Cu(NO3)2 + Al —> Al(NO3)3 + Cu

Thus, we can balance the above equation as follow:

Cu(NO3)2 + Al —> Al(NO3)3 + Cu

There are 2 atoms of N on the left side and 3 atoms on the right side. It can be balance by putting 3 in front of Cu(NO3)2 and 2 in front of Al(NO3)3 as shown below:

3Cu(NO3)2 + Al —> 2Al(NO3)3 + Cu

There are 3 atoms of Cu on the left side and 1 atom on the right side. It can be balance by putting 3 in front Cu as shown below:

3Cu(NO3)2 + Al —> 2Al(NO3)3 + 3Cu

There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Al as shown below:

3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu

Thus, the equation is balanced.

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8

c. 4.54 x 10–12 j happens to be correct