If the positive end of a water molecule were to encounter the surface shown above, what might happen to the surface’s negative charges? Explain your reasoning.

The negative charges of the surface will be attracted to the positive ends of the water molecule

Explanation:

A water molecule is a polar molecule. This means that the two ends of a water molecule are oppositely charged with one end being positive and the other end being negative.

When the positive end of a water molecule encounters a surface as shown in the attachment, where positive and negative charges are evenly distributed at rest, with the negative charges free to move, the negative charges will be attracted to the positive end of the water molecule due to the principle of electrostatics which states that unlike charges attract, while like charges repel. This means that negative and positive charges are attracted to each other while positive and positive or negative and negative charges are repelled from each other. Therefore, the water molecule will adhere to the surface because of the attraction between opposite charges.

what are the statements?

explanation:

give me the statements and i'll tell you which is correct

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :