Calculate the standard enthalpy of formation of FeS2 (s) at 565°C from the following data at 298,15 K Assume that the heat capacities are independent of temperature, Substance Fe(s) FeS2(s) Fe2O3(s) S(rhombic) SO2(g)
AH (kJ - mol )
-8242
-296.81
Cp, m/R
3.02 7.48
2.72
You are also given that for the reaction 2FeS2(s) + 402(g) → Fe, O3(s) + 4SO2(g) AH = -1655 kJ - mol!
Express your answer to four significant figures and include the appropriate units.

i had this on my unit activity, i can you if you are a plato student. are you a plato student?

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

no, the red giant is the hottest with 2.00.000.000 degrees celsius. while the white dwarf only 25,000 degrees celsius.

the answer would be a