Step 5: Calculate HTIOH- Ratios for More Extreme pH Solutions n
Find the concentration of H+ ions at a pH = 11 and
pH = 6. Then divide the concentration of Htions at a
pH = 11 by the of H+ ions at a pH = 6. Record your
answer in Table C.
What is the concentration of H+ ions at a pH = 11?
mol/L
10
What is the concentration of H* ions at a pH = 6?
mol/L
How many fewer H+ ions are there in a solution at a
pH = 11 than in a solution at a pH = 6?

Explanation:

Step 5: Calculate HTIOH- Ratios for More Extreme pH Solutions

n

Find the concentration of H+ ions at a pH = 11 and

pH = 6. Then divide the concentration of Htions at a

pH = 11 by the of H+ ions at a pH = 6. Record your

answer in Table C.

What is the concentration of H+ ions at a pH = 11?

mol/L

10

What is the concentration of H* ions at a pH = 6?

mol/L

How many fewer H+ ions are there in a solution at a

pH = 11 than in a solution at a pH = 6?

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.

what are the statements