How many moles of water vapor are in 44.8 L of water vapor (H2O) at STP

n = 2 mol

Explanation:

Given data:

Number of moles of water vapors = ?

Volume of water vapors = 44.8 L

Temperature = 273 K

Pressure = 1 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

by putting values,

1 atm × 44.8 L = n×0.0821 atm.L/ mol.K  × 273 K

44.8 L. atm = n×22.4  atm.L/ mol

n = 44.8 L. atm /22.4  atm.L/ mol

n = 2 mol

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