How many grams of AgNO3 are needed to prepare a 75.00 mL solution that is 6.5% (m/v)?

Volume of AgNO₃ = 4.9 ml (Approx)

Explanation:

Given:

Total solution = 75 ml

Volume of AgNO₃ = 6.5%

Find:

Volume of AgNO₃

Computation:

Volume of AgNO₃ = Total solution x Volume of AgNO₃

Volume of AgNO₃ = 75 x 6.5%

Volume of AgNO₃ = 4.875

Volume of AgNO₃ = 4.9 ml (Approx)

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa

i think its 100

i hope this !