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Chemistry, 04.12.2020 01:20 emilygoolsby2123
(Thinking about electronegativity differences, what type of bond would you predict
to be formed between new elements located at the bottom of columns E and G?
(DOK 2)
Ionic because the difference in electronegativity is greater than 1.7 and element
E is a metal and bonds with G, a nonmetal to combine in a 1:1 ratio.
lonic because the difference in electronegativity is greater than 0.4, but less
than 1.7 and element E is a nonmetal and bonds with G, a metal to combine in a
1:1 ratio.
Nonpolar covalent because the difference in electronegativity is relatively small
and element Eis a metal and bonds with Ga nonmetal to combine in a 1:1 ratio.
Nonpolar covalent because the difference in electronegativity is greater than 1.7
and element Eis a metal and bonds with G, a nonmetal to combine in a 1:1 ratio.
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Answer the questions about this reaction: nai(aq) + cl2(g) → nacl(aq) + i2(g) write the oxidation and reduction half-reactions: oxidation half-reaction: reduction half-reaction: based on the table of relative strengths of oxidizing and reducing agents (b-18), would these reactants form these products? write the balanced equation: answer options: a. 0/na -> +1/na+1e- b. nai(aq) + cl2(g) → nacl(aq) + i2(g) c. +1/na+1e- -> 0 /na d. -1/2i -> 0/i2+2e- e. no f. 4nai(aq) + cl2(g) → 4nacl(aq) + i2(g) g. 2nai(aq) + cl2(g) → 2nacl(aq) + i2(g) h. 4nai(aq) + 2cl2(g) → 4nacl(aq) + 2i2(g) i. nai(aq) + cl2(g) → nacl(aq) + i2(g) j. 0/cl2+2e -> -1/2cl- k. yes
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