The Henry's law constant for helium gas in water at 30 ∘C is 3.7×10−4M/atm; the constant for N2 at 30 ∘C is 6.0×10−4M/atm. a. If helium gas is present at 2.1 atm pressure, calculate the solubility of this gas.
b. If N2 is present at 2.1 atm pressure, calculate the solubility of this gas.

a. 7.8 × 10⁻⁴ M

b. 1.3 × 10⁻³ M

Explanation:

We can calculate the solubility of a gas using Henry's law.

S = k × P

where,

a. Determine the solubility of He

S = k × P

S = 3.7 × 10⁻⁴ M/atm × 2.1 atm

S = 7.8 × 10⁻⁴ M

a. Determine the solubility of N₂

S = k × P

S = 6.0 × 10⁻⁴ M/atm × 2.1 atm

S = 1.3 × 10⁻³ M

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the answer is c i took the test