How many molecules of glucose (C6H12O6,M=180.18g/mol) are contained in 144mL of 0.280 M glucose solution?

Volume of Glucose solution = 144 mL  OR 0.144 L

Molarity of Glucose solution = 0.280 M

From the definition of Molarity, we know that:

Molarity = number of moles / volume(in L)

in this equation, multiplying both sides by Volume, we get:

number of moles = Molarity*Volume(in L)

replacing the variables

Number of moles = 0.280*(0.144L)

Number of moles = 0.04

We know that:

Number of molecules = Number of Moles * Avogadro's number

Number of molecules = 0.04 * 6.022 * 10²³

Number of molecules = 0.24088 * 10²³

Number of molecules = 2.4088 * 10²²

Therefore, there are 2.4088 * 10²² molecules of Glucose in the given solution

the answer is:  

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