What is the volume in liters of 3.24 kg of ethylene glycol

1169.298 L

Explanation: In order to go from grams to liters, you must find the moles first using the molar mass, 62.068 g/mol (found via google search). I will assume the ethylene glycol is in gas form so we can use the 22.4 L per mol conversion.

Using dimensional analysis, starting with the kg, we must convert to grams, then moles, then liters.

Multiply the top individually, then the bottom individually.

Divide out.

In the end, we get 1169.298 L of ethylene glycol.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%