One way that steel makers can keep steel from rusting is to coat it with zinc metal. If the workers combine excess steel (FeNiO,) and 75.00g of zinc, how much coated steel (ZnFeNiO)
should they be able to make?


225.4 g

Explanation:

The equation of the reaction is;

Zn(s) + FeNiO(s) > ZnFeNiO(s)

Since FeNiO is in excess then Zn must be the limiting reactant.

Molar mass of Zn =  65.38gmol-1

Number of moles of Zn reacted = 75g/65.38gmol-1 =1.15 moles

If 1 mole of Zn yields 1 mole of ZnFeNiO

1.15 moles of Zn yields 1.15 moles of ZnFeNiO

Mass of ZnFeNiO produced= 196gmol-1 * 1.15moles = 225.4 g

what is the question here. i think you messed up.

answeridentity;