Barium chlorate (Ba(ClO3)2) breaks down to form barium chloride and oxygen. What is the balanced equation for this reaction? When counting atoms in parentheses multiply all subscripts by the number outside the parentheses to get the number of atoms

Ba(ClO3)2 → BaCl2 + 3O2

Explanation:

According to this question, Barium chlorate (Ba(ClO3)2) breaks down to form barium chloride (BaCl2) and oxygen (O2). The equation is as follows:

Ba(ClO3)2 → BaCl2 + O2

One would notice that this equation is not BALANCED because the number of atoms of each elements are not the same on each side of the equation.

- There is one atom of Barium (Ba) on both reactants and product side

- There are two atoms of chlorine (Cl) on both reactants and product side

- There is an unven number of atoms of oxygen on both sides. That is, 6 atoms of oxygen on reactant side but 2 atoms on product side.

To balance the number of oxygen atom, we add coefficient 3 to the oxygen atom on the product side to have 6-6 for both sides. That is;

Ba(ClO3)2 → BaCl2 + 3O2

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.