Q 1. Element M is a metal that forms compounds of the type MX2, MX3, and MX4, where X is a Chlorine (Cl). I) What is the expected trend in the ionic radius of M in these compounds?
II) Arrange these compounds in order of decreasing ionic radius of M.

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Explanation:

The ionic radius of metal M decreases as the magnitude of charge on the metal M increases. The ionic radius is the distance between the nucleus and the electron in the outermost shell of an ion. So, ionic radius decreases with increasing positive charge.

We can see that from the various formulae in the question that the metal forms cations M^2+, M^3+ and M^4+ respectively. The order of decreasing ionic radius of the compounds is;

MX2 > MX3 > MX4

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

the answer is 303.15 or 303