Air is trapped in a cylinder fitted with a piston that occupies 150.5 mL at 1.12 atm pressure. What is the new volume when the piston is depressed, increasing the pressure by 15%?

New volume V2 = 120.4 ml

Explanation:

Given:

Pressure P1 = 1.12 atm

New pressure P2 = 1.12[1+0.25] = 1.4 atm

Old volume V1 = 150.5 ml

Find:

New volume V2

Computation:

P1V1 = P2V2

(1.12)(150.5) = (1.4)(V2)

V2 = 120.4 ml

New volume V2 = 120.4 ml

it would be d. henry moseley

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for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

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