The rate constant for the radioactive decay of tritium 3H is 0.056 1/yr. The percentage of tritium remaining after 50 years is:

6.05%

Explanation:

From the question given above, the following data were obtained:

Decay constant (K) = 0.0561 /yr

Time (t) = 50 years

We can obtain the percentage of tritium remaining after 50 years by using the following formula:

Log (N₀/N) = kt /2.303

NOTE:

N₀ is the original amount.

N is the amount remaining.

K is the decay constant.

t is the time

Log (N₀/N) = (0.0561 × 50) /2.303

Log (N₀/N) = 2.805/2.303

Log (N₀/N) = 1.218

Take the anti log of 1.218

(N₀/N) = anti log (1.218)

(N₀/N) = 1.218

N₀/N = 16.52

Invert and multiply by 100 to obtain the percentage.

N/N₀ = 1/16.52 × 100

N/N₀ = 6.05%

Thus, the percentage of tritium remaining after 50 years is 6.05%

false

because it does not have the potential to be entirely used up

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)