A beaker contains 318 mL m
L
of a 5.75 M
M
HCl(aq)
H
C
l
(
a
q
)
solution. Determine the new concentration of the solution after it is diluted by adding 143 mL
m
L
of water to the beaker.

3.97 M

Explanation:

Given data:

Initial volume V₁  = 318 mL

Initial molarity M₁ = 5.75 M

New volume V₂=  461 mL

New concentration M₂= ?

Solution:

New volume V₂= 143 mL+ 318 mL

New volume V₂= 461 mL

Formula:

M₁V₁  = M₂V₂

M₂ = M₁V₁ / V₂

M₂ = 5.75 M × 318 mL / 461 mL

M₂ = 1828.5 M. mL/ 461 mL

M₂ = 3.97 M

explanation:

two years ago, when picking flowers in the mountains back of yosemite valley, i found a book. it was blotted and storm-beaten; all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however; many of the inner pages were well preserved. and although all were more or less stained and torn, whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today; its granite pages have been torn and blurred by the same storms that wasted the castaway book.

two years ago, when picking flowers in the mountains back of yosemite valley; i found a book. it was blotted and storm-beaten, all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however, many of the inner pages were well preserved. and although all were more or less stained and torn; whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today, its granite pages have been torn and blurred by the same storms that wasted the castaway book.