If I start with 0.0350 L of a 12.0 M hydrochloric acid solution, and dilute it with water to a new volume of 1.20 L, what is the new concentration?

0.35 M

Explanation:

Using the formula; C1V1 = C2V2

Where;

C1 = concentration of initial solution

C2 = concentration of final solution

V1 = volume of initial solution

V2 = volume of final solution

Based on this question, I start with 0.0350 L of a 12.0 M hydrochloric acid solution, and dilute it with water to a new volume of 1.20 L. This means that:

C1 = 12.0 M, V1 = 0.0350 L, V2 = 1.20 L, C2 = ?

Hence, C1V1 = C2V2

12 × 0.0350 = C2 × 1.20

0.42 = 1.2C2

C2 = 0.42/1.2

C2 = 0.35 M

your answer would be a. 12.5 kg