Estado de oxidacion de SO42-, NO2-, SiO32- y K2Cr2O7 urgenteee D:

oxidation state of SO42-, NO2-, SiO32- and K2Cr2O7

2-

1-

2-

0

Explanation:

The oxidation states of the ions and compounds is given as;

SO₄²⁻  = 2-

NO₂⁻ = 1-

SiO₃²⁻  = 2-

K₂Cr₂O₇  = 0

Here are some rules that governs assignment of oxidation states;

1. For elements in uncombined states, the oxidation state is 0

2. For simple ions, the oxidation number is the actual charge carried.

3. The algebraic sum of all oxidation number of all atoms in a neutral compound is zero.

radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold

the nucleus together due to an excess of either protons or neutrons.

the product of the pressure and volume is also constant