How many grams of Phosphorus is required to complete combustion of 40g Oxygen P+O2-mm>P2O5 . Please balance

Mass = 31 g

Explanation:

Given data:

Mass of phosphorus required = ?

Mass of oxygen = 40 g

Solution:

Chemical equation:

4P + 5O₂     →     2P₂O₅

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 40 g/ 32 g/mol

Number of moles = 1.25 mol

Now we will compare the moles of P and oxygen.

                      O₂             :            P

                       5              :            4

                      1.25          :         4/5×1.25 = 1

Mass of phosphorus:

Mass = number of moles × molar mass

Mass = 1 mol × 31 g/mol

Mass = 31 g

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

i don't see a text, but i am gonna assume this *orbit* the curved path, usually elliptical, described by a planet, satellite, spaceship, etc., around a celestial body, as the sun.