How many molecules (or atoms) of tin (IV) nitrate would contain 6.17 moles of
oxygen atoms?

3.01 x 10²³ molecules

Explanation:

Given parameters:

Number of moles of oxygen atoms  = 6.17moles

Unknown:

Number of molecule of tin(IV) nitrate  = ?

Solution:

To solve this problem, let us write the formula of tin (IV) nitrate;

              N₄O₁₂Sn

Now,

       12 moles of Oxygen can be found in 1 mole of  N₄O₁₂Sn

      6.17 moles of oxygen will be found in   = 0.5mole of  N₄O₁₂Sn

So;

       1 mole of a substance contains 6.02 x 10²³ molecules

  0.5 mole of N₄O₁₂Sn will contain 0.5 x 6.02 x 10²³ = 3.01 x 10²³ molecules

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