Which orbitals cannot exist?
2p 3p 4d 3f 6s 2d
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The orbitals 3f and 2d cannot exist.

Explanation:

Hello!

In this case, considering the attached picture in which you find each energy level with the corresponding number of subshells, it is possible to infer level one has s subshell only, level 2 s and p, level 3 has s, p and d and from level 4 to 7 have s, p, d f, therefore, the orbitals 3f and 2d cannot exist.

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answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

b.final