A piston contains 0.39L of air at 1.0 atm. If the pressure on the piston is increased to 5.6 atm, what is the new volume?

The new volume : 0.07 L

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

P₁=1 atm

V₁=0.39 L

P₂=5.6 atm

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol