A quantity of gas under a pressure of 302kpa has a volume of 600cm3. The pressure is increased to 604kPa, while the temperature is kept constant. What is the new volume?

V₂ = 300  cm³

Explanation:

Given data:

Initial pressure = 302 KPa

Initial volume = 600 cm³

Final pressure = 604 KPa

Final volume = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

302 KPa × 600 cm³ = 604 KPa× V₂

V₂ = 181200 KPa.cm³ / 604 KPa

V₂ = 300  cm³

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles