Use the activity series below to predict whether the following reactions will take place. Activity series from most to least reactive: Upper F Subscript 2; Upper C l Subscript 2; Upper B r Subscript 2; Upper I Subscript 2. Cl2 + 2RbI → 2RbCl + I2 yes no I2 + NiBr2 → NiI2 + Br2 yes no

Cl2 + 2RbI → 2RbCl + I2  is possible while I2 + NiBr2 → NiI2 + Br2 is not possible.

It will do us a lot of good to write out the equations again;

Cl2 + 2RbI → 2RbCl + I2       Yes

I2 + NiBr2 → NiI2 + Br2         No

If we look at the reaction closely, they are displacement reactions. It is worthy to note that a specie can only displace another specie which lies below it in the activity series. The activity series is an arrangement of elements in order of decreasing reactivity.

The activity series of the halogens is; fluorine > chlorine > bromine > iodine.

Since chlorine is above iodine in the activity series, Cl2 + 2RbI → 2RbCl + I2 is possible.

Iodine is less than bromine in the activity series hence the reaction  I2 + NiBr2 → NiI2 + Br2 is not possible.

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Cl2 + 2RbI --> 2RbCl + I2 = yes

I2 + NiBr2 --> NiI2 + Br2 = no

Explanation:

I just took the assinment

answer; i believe that the correct answer is (a) potassium(k)