It took 2.35 min with a current of 2.12 A to plate out all the silver from 0.250 L of a solution containing Ag . What was the original concentration of Ag in the solution

concentration of Ag = 1.34 g / L .

Explanation:

Quantity of charge = 2.35 x 60 x 2.12 = 298.92 coulomb.

equivalent weight of silver = 108 g .

96500 coulomb deposits 108 g of silver

298.92 coulomb will deposit 108 x 298.92 / 96500 g

= .3345 g . of silver .

.250 L contains .3345 g of silver

1 L contains .3345 x 4 = 1.34 g

concentration of Ag = 1.34 g / L .

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8