A sample of water (88 grams) had a temperature change of 6.0 ℃. What was the heat change of this sample? (q = m c ΔT, c = 4.18 J/ g ℃)

Explanation:

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In this case, since the heat involved during a heating process is computed in terms of mass, specific heat and temperature change as shown below:

Thus, since the heated mass of water was 88 g, the specific heat of water is 4.184 J/g°C and the temperature change is 6.0 °C, we can compute the heat as shown below:

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c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.