The value of ΔH° for the reaction below is -336 kJ. Calculate the heat (kJ) released to the surroundings when 23.0 g of HCl is formed. CH4(g) + 3Cl2(g) → CHCl3(l) + 3HCl(g)

The heat (kJ) released to the surroundings at the given equation is 70.7KJ.

We know that

= 0.631 mole

Since energy should be related at the time when 3 moles of HCI should be generated = 336 K

Now energy released is  

= 70.65 kJ

Hence we can conclude that heat released to the surrounding is 70.7 kJ.

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The heat (kJ) released to the surroundings : -70.56 kJ

Reaction

CH₄(g) + 3Cl₂(g) → CHCl₃(l) + 3HCl(g) ΔH°=-336 kJ

For 3 mol HCl formed ⇒ ΔH°=-336 kJ

23.0 g of HCl :

Heat released for 0.63 mol HCl :

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