What mass of sodium carbonate is required for complete reaction with 8.35 g of nitric acid to produce sodium nitrate, carbon dioxide, and water?

The mass of sodium carbonate that is required for complete reaction with 8.35 grams of nitric acid is equal to 7.02 grams.

Given the following data:

Scientific data:

To determine the mass of sodium carbonate that is required for complete reaction with 8.35 grams of nitric acid:

First of all, we would write the properly balanced chemical equation for this chemical reaction:

Next, we would find the number of moles of nitric acid () required:

Number of moles = 0.1325 moles.

By stoichiometry:

2 moles of = 1 mole of

0.1325 moles of = X mole of

Cross-multiplying, we have:

X = 0.0663 moles

Now, we can determine the mass of sodium carbonate that is required:

Mass of = 7.02 grams

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Mass of sodium carbonate = 7.022 g

Reaction

Na₂CO₃ + 2HNO₃ ⇒ 2NaNO₃ + H₂O + CO₂

mol of HNO₃ (MW=63,01 g/mol):

mol Na₂CO₃

mass Na₂CO₃(MW = 105,9888 g/mol) :

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