200 mL of nitrogen gas at 24K is heated to 47K.

See explanation

Explanation:

The question is incomplete. However, base on the given information, one likely question could be that, we calculate the the volume of the nitrogen gas after heating it.

So, we have that:

Initial Volume, V1 = 200mL

Initial Temperature, T1 = 24k

Final Temperature, T2 = 47k

To solve the final volume of the gas, we apply the following ideal gas law equation

V1 * T1 = V2 * T2

Substitute values for V1, T1 and T2

200mL * 24K = V2 * 47K

200mL * 24 = V2 * 47

4800mL = 47V2

Solve for V2

V2 = 4800/47

V2 = 102.13 mL Approximated

Hence, the volume of nitrogen gas after heating is 102.13mL

neutrons are in the middle of the atom and the electrons, which are much smaller.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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