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Chemistry, 13.11.2020 16:50 rara54

Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)2(aq)+2NH4I(aq)⟶PbI2(s)+2NH4 NO3(aq) What volume of a 0.590 M NH4I solution is required to react with 617 mL of a 0.560 M Pb(NO3)2 solution?

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Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to...

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